Derivative of x+e^x

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     x
x + E

$$e^{x} + x$$

x + E^x

Detail solution

Differentiate $e^{x} + x$ term by term:
1. Apply the power rule: $x$ goes to $1$
2. The derivative of $e^{x}$ is itself.
The result is: $e^{x} + 1$

The answer is:

$e^{x} + 1$

The graph

Plot the graph f(x)

Plot the graph f'(x)

The first derivative [src]

     x
1 + E

$$e^{x} + 1$$

Simplify

The second derivative [src]

x
E

$$e^{x}$$

Simplify

The third derivative [src]

x
E

$$e^{x}$$

Simplify

The graph