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3*sin(x)*cos(x)

Derivative of 3*sin(x)*cos(x)

Function f() - derivative -N order at the point
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The solution

You have entered [src]
3*sin(x)*cos(x)
3sin(x)cos(x)3 \sin{\left(x \right)} \cos{\left(x \right)}
(3*sin(x))*cos(x)
Detail solution
  1. Apply the product rule:

    ddxf(x)g(x)=f(x)ddxg(x)+g(x)ddxf(x)\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}

    f(x)=3sin(x)f{\left(x \right)} = 3 \sin{\left(x \right)}; to find ddxf(x)\frac{d}{d x} f{\left(x \right)}:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. The derivative of sine is cosine:

        ddxsin(x)=cos(x)\frac{d}{d x} \sin{\left(x \right)} = \cos{\left(x \right)}

      So, the result is: 3cos(x)3 \cos{\left(x \right)}

    g(x)=cos(x)g{\left(x \right)} = \cos{\left(x \right)}; to find ddxg(x)\frac{d}{d x} g{\left(x \right)}:

    1. The derivative of cosine is negative sine:

      ddxcos(x)=sin(x)\frac{d}{d x} \cos{\left(x \right)} = - \sin{\left(x \right)}

    The result is: 3sin2(x)+3cos2(x)- 3 \sin^{2}{\left(x \right)} + 3 \cos^{2}{\left(x \right)}

  2. Now simplify:

    3cos(2x)3 \cos{\left(2 x \right)}


The answer is:

3cos(2x)3 \cos{\left(2 x \right)}

The graph
02468-8-6-4-2-10105-5
The first derivative [src]
       2           2   
- 3*sin (x) + 3*cos (x)
3sin2(x)+3cos2(x)- 3 \sin^{2}{\left(x \right)} + 3 \cos^{2}{\left(x \right)}
The second derivative [src]
-12*cos(x)*sin(x)
12sin(x)cos(x)- 12 \sin{\left(x \right)} \cos{\left(x \right)}
The third derivative [src]
   /   2         2   \
12*\sin (x) - cos (x)/
12(sin2(x)cos2(x))12 \left(\sin^{2}{\left(x \right)} - \cos^{2}{\left(x \right)}\right)
The graph
Derivative of 3*sin(x)*cos(x)