9 sin (x)
sin(x)^9
Let u=sin(x)u = \sin{\left(x \right)}u=sin(x).
Apply the power rule: u9u^{9}u9 goes to 9u89 u^{8}9u8
Then, apply the chain rule. Multiply by ddxsin(x)\frac{d}{d x} \sin{\left(x \right)}dxdsin(x):
The derivative of sine is cosine:
The result of the chain rule is:
The answer is:
8 9*sin (x)*cos(x)
7 / 2 2 \ 9*sin (x)*\- sin (x) + 8*cos (x)/
6 / 2 2 \ 9*sin (x)*\- 25*sin (x) + 56*cos (x)/*cos(x)