4 sin (x)
sin(x)^4
Let u=sin(x)u = \sin{\left(x \right)}u=sin(x).
Apply the power rule: u4u^{4}u4 goes to 4u34 u^{3}4u3
Then, apply the chain rule. Multiply by ddxsin(x)\frac{d}{d x} \sin{\left(x \right)}dxdsin(x):
The derivative of sine is cosine:
The result of the chain rule is:
The answer is:
3 4*sin (x)*cos(x)
2 / 2 2 \ 4*sin (x)*\- sin (x) + 3*cos (x)/
/ 2 2 \ 8*\- 5*sin (x) + 3*cos (x)/*cos(x)*sin(x)