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Derivative of sin3x+2sin^3*(x)

Function f() - derivative -N order at the point
v

The graph:

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The solution

You have entered [src]
                3   
sin(3*x) + 2*sin (x)
$$2 \sin^{3}{\left(x \right)} + \sin{\left(3 x \right)}$$
sin(3*x) + 2*sin(x)^3
Detail solution
  1. Differentiate term by term:

    1. Let .

    2. The derivative of sine is cosine:

    3. Then, apply the chain rule. Multiply by :

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result of the chain rule is:

    4. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. Apply the power rule: goes to

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of sine is cosine:

        The result of the chain rule is:

      So, the result is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
                  2          
3*cos(3*x) + 6*sin (x)*cos(x)
$$6 \sin^{2}{\left(x \right)} \cos{\left(x \right)} + 3 \cos{\left(3 x \right)}$$
The second derivative [src]
  /                   3           2          \
3*\-3*sin(3*x) - 2*sin (x) + 4*cos (x)*sin(x)/
$$3 \left(- 2 \sin^{3}{\left(x \right)} + 4 \sin{\left(x \right)} \cos^{2}{\left(x \right)} - 3 \sin{\left(3 x \right)}\right)$$
The third derivative [src]
  /                   3            2          \
3*\-9*cos(3*x) + 4*cos (x) - 14*sin (x)*cos(x)/
$$3 \left(- 14 \sin^{2}{\left(x \right)} \cos{\left(x \right)} + 4 \cos^{3}{\left(x \right)} - 9 \cos{\left(3 x \right)}\right)$$