sin(log(x))
Let u=log(x)u = \log{\left(x \right)}u=log(x).
The derivative of sine is cosine:
Then, apply the chain rule. Multiply by ddxlog(x)\frac{d}{d x} \log{\left(x \right)}dxdlog(x):
The derivative of log(x)\log{\left(x \right)}log(x) is 1x\frac{1}{x}x1.
The result of the chain rule is:
The answer is:
cos(log(x)) ----------- x
-(cos(log(x)) + sin(log(x))) ----------------------------- 2 x
3*sin(log(x)) + cos(log(x)) --------------------------- 3 x