Derivative of 1/cos(x)

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  1   
------
cos(x)

$$\frac{1}{\cos{\left(x \right)}}$$

1/cos(x)

Detail solution

Let $u = \cos{\left(x \right)}$ .
Apply the power rule: $\frac{1}{u}$ goes to $- \frac{1}{u^{2}}$
Then, apply the chain rule. Multiply by $\frac{d}{d x} \cos{\left(x \right)}$ :
1. The derivative of cosine is negative sine:
  
  $\frac{d}{d x} \cos{\left(x \right)} = - \sin{\left(x \right)}$
The result of the chain rule is:

$\frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}$

The answer is:

$\frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}$

The graph

Plot the graph f(x)

Plot the graph f'(x)

The first derivative [src]

 sin(x)
-------
   2   
cos (x)

$$\frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}$$

Simplify

The second derivative [src]

         2   
    2*sin (x)
1 + ---------
        2    
     cos (x) 
-------------
    cos(x)

$$\frac{\frac{2 \sin^{2}{\left(x \right)}}{\cos^{2}{\left(x \right)}} + 1}{\cos{\left(x \right)}}$$

Simplify

The third derivative [src]

/         2   \       
|    6*sin (x)|       
|5 + ---------|*sin(x)
|        2    |       
\     cos (x) /       
----------------------
          2           
       cos (x)

$$\frac{\left(\frac{6 \sin^{2}{\left(x \right)}}{\cos^{2}{\left(x \right)}} + 5\right) \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}$$

Simplify

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Derivative of 1/cos(x)

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