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Derivative of ln((2x+1)^(1/2))

Function f() - derivative -N order at the point
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The solution

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   /  _________\
log\\/ 2*x + 1 /
log(2x+1)\log{\left(\sqrt{2 x + 1} \right)}
log(sqrt(2*x + 1))
Detail solution
  1. Let u=2x+1u = \sqrt{2 x + 1}.

  2. The derivative of log(u)\log{\left(u \right)} is 1u\frac{1}{u}.

  3. Then, apply the chain rule. Multiply by ddx2x+1\frac{d}{d x} \sqrt{2 x + 1}:

    1. Let u=2x+1u = 2 x + 1.

    2. Apply the power rule: u\sqrt{u} goes to 12u\frac{1}{2 \sqrt{u}}

    3. Then, apply the chain rule. Multiply by ddx(2x+1)\frac{d}{d x} \left(2 x + 1\right):

      1. Differentiate 2x+12 x + 1 term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: xx goes to 11

          So, the result is: 22

        2. The derivative of the constant 11 is zero.

        The result is: 22

      The result of the chain rule is:

      12x+1\frac{1}{\sqrt{2 x + 1}}

    The result of the chain rule is:

    12x+1\frac{1}{2 x + 1}

  4. Now simplify:

    12x+1\frac{1}{2 x + 1}


The answer is:

12x+1\frac{1}{2 x + 1}

The graph
02468-8-6-4-2-1010-200100
The first derivative [src]
   1   
-------
2*x + 1
12x+1\frac{1}{2 x + 1}
The second derivative [src]
   -2     
----------
         2
(1 + 2*x) 
2(2x+1)2- \frac{2}{\left(2 x + 1\right)^{2}}
The third derivative [src]
    8     
----------
         3
(1 + 2*x) 
8(2x+1)3\frac{8}{\left(2 x + 1\right)^{3}}