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Derivative of a*sinx^2+1

Function f() - derivative -N order at the point
v

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The solution

You have entered [src]
     2       
a*sin (x) + 1
$$a \sin^{2}{\left(x \right)} + 1$$
d /     2       \
--\a*sin (x) + 1/
dx               
$$\frac{\partial}{\partial x} \left(a \sin^{2}{\left(x \right)} + 1\right)$$
Detail solution
  1. Differentiate term by term:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. Apply the power rule: goes to

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of sine is cosine:

        The result of the chain rule is:

      So, the result is:

    2. The derivative of the constant is zero.

    The result is:

  2. Now simplify:


The answer is:

The first derivative [src]
2*a*cos(x)*sin(x)
$$2 a \sin{\left(x \right)} \cos{\left(x \right)}$$
The second derivative [src]
    /   2         2   \
2*a*\cos (x) - sin (x)/
$$2 a \left(- \sin^{2}{\left(x \right)} + \cos^{2}{\left(x \right)}\right)$$
The third derivative [src]
-8*a*cos(x)*sin(x)
$$- 8 a \sin{\left(x \right)} \cos{\left(x \right)}$$