Derivative of 3sin2x*cosx

1. The derivative of a constant times a function is the constant times the derivative of the function.

   1. Apply the product rule:

      $$\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}$$

      $f{\left(x \right)} = \cos{\left(x \right)}$; to find $\frac{d}{d x} f{\left(x \right)}$:

      1. The derivative of cosine is negative sine:

         $$\frac{d}{d x} \cos{\left(x \right)} = - \sin{\left(x \right)}$$

      $g{\left(x \right)} = \sin{\left(2 x \right)}$; to find $\frac{d}{d x} g{\left(x \right)}$:

      1. Let $u = 2 x$.

      2. The derivative of sine is cosine:

         $$\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}$$

      3. Then, apply the chain rule. Multiply by $\frac{d}{d x} 2 x$:

         1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: $x$ goes to $1$

            So, the result is: $2$

         The result of the chain rule is:

         $$2 \cos{\left(2 x \right)}$$

      The result is: $- \sin{\left(x \right)} \sin{\left(2 x \right)} + 2 \cos{\left(x \right)} \cos{\left(2 x \right)}$

   So, the result is: $- 3 \sin{\left(x \right)} \sin{\left(2 x \right)} + 6 \cos{\left(x \right)} \cos{\left(2 x \right)}$

2. Now simplify:

   $$\frac{3 \cos{\left(x \right)}}{2} + \frac{9 \cos{\left(3 x \right)}}{2}$$

The answer is:

$$\frac{3 \cos{\left(x \right)}}{2} + \frac{9 \cos{\left(3 x \right)}}{2}$$