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Derivative of 2x-3/sinx/4

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
      /  3   \
      |------|
      \sin(x)/
2*x - --------
         4    
$$2 x - \frac{3 \frac{1}{\sin{\left(x \right)}}}{4}$$
2*x - 3/sin(x)/4
Detail solution
  1. Differentiate term by term:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: goes to

      So, the result is:

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Let .

        2. Apply the power rule: goes to

        3. Then, apply the chain rule. Multiply by :

          1. The derivative of sine is cosine:

          The result of the chain rule is:

        So, the result is:

      So, the result is:

    The result is:


The answer is:

The graph
The first derivative [src]
     3*cos(x)
2 + ---------
         2   
    4*sin (x)
$$2 + \frac{3 \cos{\left(x \right)}}{4 \sin^{2}{\left(x \right)}}$$
The second derivative [src]
   /         2   \
   |    2*cos (x)|
-3*|1 + ---------|
   |        2    |
   \     sin (x) /
------------------
     4*sin(x)     
$$- \frac{3 \left(1 + \frac{2 \cos^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}}\right)}{4 \sin{\left(x \right)}}$$
The third derivative [src]
  /         2   \       
  |    6*cos (x)|       
3*|5 + ---------|*cos(x)
  |        2    |       
  \     sin (x) /       
------------------------
            2           
       4*sin (x)        
$$\frac{3 \left(5 + \frac{6 \cos^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}}\right) \cos{\left(x \right)}}{4 \sin^{2}{\left(x \right)}}$$