Mister Exam

Derivative of 2cos5x

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
2*cos(5*x)
2cos(5x)2 \cos{\left(5 x \right)}
d             
--(2*cos(5*x))
dx            
ddx2cos(5x)\frac{d}{d x} 2 \cos{\left(5 x \right)}
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Let u=5xu = 5 x.

    2. The derivative of cosine is negative sine:

      dducos(u)=sin(u)\frac{d}{d u} \cos{\left(u \right)} = - \sin{\left(u \right)}

    3. Then, apply the chain rule. Multiply by ddx5x\frac{d}{d x} 5 x:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: xx goes to 11

        So, the result is: 55

      The result of the chain rule is:

      5sin(5x)- 5 \sin{\left(5 x \right)}

    So, the result is: 10sin(5x)- 10 \sin{\left(5 x \right)}


The answer is:

10sin(5x)- 10 \sin{\left(5 x \right)}

The graph
02468-8-6-4-2-1010-2020
The first derivative [src]
-10*sin(5*x)
10sin(5x)- 10 \sin{\left(5 x \right)}
The second derivative [src]
-50*cos(5*x)
50cos(5x)- 50 \cos{\left(5 x \right)}
The third derivative [src]
250*sin(5*x)
250sin(5x)250 \sin{\left(5 x \right)}
The graph
Derivative of 2cos5x