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(x-y)^2; (y-x)^2

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The solution

You have entered [src]
       2    
(x - y)  = 0
$$\left(x - y\right)^{2} = 0$$
       2    
(y - x)  = 0
$$\left(- x + y\right)^{2} = 0$$
(-x + y)^2 = 0
Rapid solution
$$x_{1} = y$$
=
$$y$$
=
y
Numerical answer [src]
x1 = 2.0
y1 = 2.0
x2 = 10.0
y2 = 10.0
x3 = 6.0
y3 = 6.0
x4 = -2.0
y4 = -2.0
x5 = -10.0
y5 = -10.0
x6 = -6.0
y6 = -6.0
x6 = -6.0
y6 = -6.0