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Sum of series x^2j



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The solution

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  oo      
 ___      
 \  `     
  \    2  
  /   x *j
 /__,     
j = 7     
j=7jx2\sum_{j=7}^{\infty} j x^{2}
Sum(x^2*j, (j, 7, oo))
The radius of convergence of the power series
Given number:
jx2j x^{2}
It is a series of species
aj(cxx0)dja_{j} \left(c x - x_{0}\right)^{d j}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limjajaj+1cR^{d} = \frac{x_{0} + \lim_{j \to \infty} \left|{\frac{a_{j}}{a_{j + 1}}}\right|}{c}
In this case
aj=jx2a_{j} = j x^{2}
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=limj(jj+1)1 = \lim_{j \to \infty}\left(\frac{j}{j + 1}\right)
Let's take the limit
we find
True

False
The answer [src]
    2
oo*x 
x2\infty x^{2}
oo*x^2

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