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Sum of series (x-y)^2



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The solution

You have entered [src]
  11          
 ___          
 \  `         
  \          2
  /   (x - y) 
 /__,         
n = 1         
$$\sum_{n=1}^{11} \left(x - y\right)^{2}$$
Sum((x - y)^2, (n, 1, 11))
The answer [src]
          2
11*(x - y) 
$$11 \left(x - y\right)^{2}$$
11*(x - y)^2

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