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Sum of series (2i+1)/n^2



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The solution

You have entered [src]
  oo         
____         
\   `        
 \    2*I + 1
  \   -------
  /       2  
 /       n   
/___,        
n = 1        
$$\sum_{n=1}^{\infty} \frac{1 + 2 i}{n^{2}}$$
Sum((2*i + 1)/n^2, (n, 1, oo))
The radius of convergence of the power series
Given number:
$$\frac{1 + 2 i}{n^{2}}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{1 + 2 i}{n^{2}}$$
and
$$x_{0} = 0$$
,
$$d = 0$$
,
$$c = 1$$
then
$$1 = \lim_{n \to \infty}\left(\frac{\left(n + 1\right)^{2}}{n^{2}}\right)$$
Let's take the limit
we find
True

False
The answer [src]
  2       2
pi    I*pi 
--- + -----
 6      3  
$$\frac{\pi^{2}}{6} + \frac{i \pi^{2}}{3}$$
pi^2/6 + i*pi^2/3
Numerical answer [src]
1.64493406684822643647241516665 + 3.28986813369645287294483033329*i
1.64493406684822643647241516665 + 3.28986813369645287294483033329*i

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