Given number:
$$\frac{\sqrt{n} \operatorname{asin}{\left(n + 1 \right)}}{n^{3} - 2}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{\sqrt{n} \operatorname{asin}{\left(n + 1 \right)}}{n^{3} - 2}$$
and
$$x_{0} = 0$$
,
$$d = 0$$
,
$$c = 1$$
then
$$1 = \lim_{n \to \infty}\left(\frac{\sqrt{n} \left|{\frac{\left(\left(n + 1\right)^{3} - 2\right) \operatorname{asin}{\left(n + 1 \right)}}{\left(n^{3} - 2\right) \operatorname{asin}{\left(n + 2 \right)}}}\right|}{\sqrt{n + 1}}\right)$$
Let's take the limitwe find
$$1 = \lim_{n \to \infty}\left(\frac{\sqrt{n} \left|{\frac{\left(\left(n + 1\right)^{3} - 2\right) \operatorname{asin}{\left(n + 1 \right)}}{\left(n^{3} - 2\right) \operatorname{asin}{\left(n + 2 \right)}}}\right|}{\sqrt{n + 1}}\right)$$
False