Given number:
$$\frac{\left(6 x - 1\right)^{n}}{6^{n} \left(n + 1\right)}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{6^{- n}}{n + 1}$$
and
$$x_{0} = 1$$
,
$$d = 1$$
,
$$c = 6$$
then
$$R = \frac{1 + \lim_{n \to \infty}\left(\frac{6^{- n} 6^{n + 1} \left(n + 2\right)}{n + 1}\right)}{6}$$
Let's take the limitwe find
$$R = \frac{7}{6}$$