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6/9n^2+12n-5

Sum of series 6/9n^2+12n-5



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The solution

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  oo                   
____                   
\   `                  
 \    /   2           \
  \   |2*n            |
  /   |---- + 12*n - 5|
 /    \ 3             /
/___,                  
n = 1                  
n=1((2n23+12n)5)\sum_{n=1}^{\infty} \left(\left(\frac{2 n^{2}}{3} + 12 n\right) - 5\right)
Sum(2*n^2/3 + 12*n - 5, (n, 1, oo))
The radius of convergence of the power series
Given number:
(2n23+12n)5\left(\frac{2 n^{2}}{3} + 12 n\right) - 5
It is a series of species
an(cxx0)dna_{n} \left(c x - x_{0}\right)^{d n}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limnanan+1cR^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}
In this case
an=2n23+12n5a_{n} = \frac{2 n^{2}}{3} + 12 n - 5
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=limn(2n23+12n512n+2(n+1)23+7)1 = \lim_{n \to \infty}\left(\frac{\left|{\frac{2 n^{2}}{3} + 12 n - 5}\right|}{12 n + \frac{2 \left(n + 1\right)^{2}}{3} + 7}\right)
Let's take the limit
we find
True

False
The rate of convergence of the power series
1.07.01.52.02.53.03.54.04.55.05.56.06.50500
Numerical answer
The series diverges
The graph
Sum of series 6/9n^2+12n-5

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