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Sum of series:
3^(n-1)/8^(n-1)
(-1)^n*2^n/factorial(n)
sin(x/2^n)*cos(3*x/2^n)
(2*x-6*y)*(3*x-5*y)+8*m*n
Identical expressions
one /sqr^ six (2n+ three)^ seven
1 divide by sqr to the power of 6(2n plus 3) to the power of 7
one divide by sqr to the power of six (2n plus three) to the power of seven
1/sqr6(2n+3)7
1/sqr62n+37
1/sqr⁶(2n+3)⁷
1/sqr^62n+3^7
1 divide by sqr^6(2n+3)^7
Similar expressions
1/sqr^6(2n-3)^7

Sum of series 1/sqr^6(2n+3)^7

The solution

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  oo                                                                                                               
____                                                                                                               
\   `                                                                                                              
 \                                                          1                                                      
  \   -------------------------------------------------------------------------------------------------------------
  /            4011991914547630480065053387702443812690402487741812225955731622655455723258857248542161222254985216
 /    (2*n + 3)                                                                                                    
/___,                                                                                                              
n = 1

$$\sum_{n=1}^{\infty} \frac{1}{\left(2 n + 3\right)^{4011991914547630480065053387702443812690402487741812225955731622655455723258857248542161222254985216}}$$

Sum(1/((2*n + 3)^4011991914547630480065053387702443812690402487741812225955731622655455723258857248542161222254985216), (n, 1, oo))

Examples of finding the sum of a series

The Sum of the Power Series
```
x^n/n
```
```
(x-1)^n
```
Factorial
```
1/2^(n!)
```
```
n^2/n!
```
```
x^n/n!
```
```
k!/(n!*(n+k)!)
```
Flint Hills Series
```
csc(n)^2/n^3
```
Basel problem
```
1/n^2
```
```
1/n^4
```
```
1/n^6
```
Harmonic series
```
1/n
```
Grandi's series
```
(-1)^n
```
Alternating series
```
(-1)^(n + 1)/n
```
```
(n + 2)*(-1)^(n - 1)
```
```
(3*n - 1)/(-5)^n
```
```
(-1)^(n - 1)*n/(6*n - 5)
```
Newton–Mercator series
```
(-1)^(n + 1)/n*x^n
```
Exam the series for convergence
```
(3*n - 1)/(-5)^n
```

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Identical expressions

Similar expressions

Sum of series 1/sqr^6(2n+3)^7

The solution

Examples of finding the sum of a series