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1/(n+2)^4

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  • Sum of series:
  • 1/(3n+1)(3n+4) 1/(3n+1)(3n+4)
  • 38 38
  • sen(na)
  • 1/(n+2)^4 1/(n+2)^4

  • Identical expressions

  • one /(n+ two)^ four
  • 1 divide by (n plus 2) to the power of 4
  • one divide by (n plus two) to the power of four
  • 1/(n+2)4
  • 1/n+24
  • 1/(n+2)⁴
  • 1/n+2^4
  • 1 divide by (n+2)^4

  • Similar expressions

  • 1/(n-2)^4
Sum of series/ 1/(n+2)^4

Sum of series 1/(n+2)^4


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The solution

You have entered [src] 
  oo          
____          
\   `         
 \       1    
  \   --------
  /          4
 /    (n + 2) 
/___,         
n = 1
∑n=1∞1(n+2)4\sum_{n=1}^{\infty} \frac{1}{\left(n + 2\right)^{4}} 
Sum(1/((n + 2)^4), (n, 1, oo))
The radius of convergence of the power series
Given number:
1(n+2)4\frac{1}{\left(n + 2\right)^{4}}
It is a series of species
an(cx−x0)dna_{n} \left(c x - x_{0}\right)^{d n}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+lim⁡n→∞∣anan+1∣cR^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}
In this case
an=1(n+2)4a_{n} = \frac{1}{\left(n + 2\right)^{4}}
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=lim⁡n→∞((n+3)4(n+2)4)1 = \lim_{n \to \infty}\left(\frac{\left(n + 3\right)^{4}}{\left(n + 2\right)^{4}}\right)
Let's take the limit
we find
True

False
The rate of convergence of the power series
1.07.01.52.02.53.03.54.04.55.05.56.06.50.0100.020
The answer [src] 
         4
  17   pi 
- -- + ---
  16    90
−1716+π490- \frac{17}{16} + \frac{\pi^{4}}{90} 
-17/16 + pi^4/90
Numerical answer [src] 
0.0198232337111381915160036965412
0.0198232337111381915160036965412
The graph
Sum of series 1/(n+2)^4

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