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1/factorial(k^2)

How to use it?
Sum of series:
2(1/(n^2+5n+6))
((n+1)^n*3^(2n-1))/(2n+1)!
log(n-i)
1/(2n+5)*(2n+7)
Identical expressions
one /factorial(k^ two)
1 divide by factorial(k squared )
one divide by factorial(k to the power of two)
1/factorial(k2)
1/factorialk2
1/factorial(k²)
1/factorial(k to the power of 2)
1/factorialk^2
1 divide by factorial(k^2)

Sum of series/ 1/factorial(k^2)

Sum of series 1/factorial(k^2)

The solution

You have entered [src]

  2        
____       
\   `      
 \      1  
  \   -----
  /   / 2\ 
 /    \k /!
/___,      
k = 1

$$\sum_{k=1}^{2} \frac{1}{\left(k^{2}\right)!}$$

Sum(1/factorial(k^2), (k, 1, 2))

The rate of convergence of the power series

The answer [src]

25
--
24

$$\frac{25}{24}$$

25/24

Numerical answer [src]

1.04166666666666666666666666667

1.04166666666666666666666666667

The graph

Sum of series 1/factorial(k^2)

Examples of finding the sum of a series

The Sum of the Power Series
```
x^n/n
```
```
(x-1)^n
```
Factorial
```
1/2^(n!)
```
```
n^2/n!
```
```
x^n/n!
```
```
k!/(n!*(n+k)!)
```
Flint Hills Series
```
csc(n)^2/n^3
```
Basel problem
```
1/n^2
```
```
1/n^4
```
```
1/n^6
```
Harmonic series
```
1/n
```
Grandi's series
```
(-1)^n
```
Alternating series
```
(-1)^(n + 1)/n
```
```
(n + 2)*(-1)^(n - 1)
```
```
(3*n - 1)/(-5)^n
```
```
(-1)^(n - 1)*n/(6*n - 5)
```
Newton–Mercator series
```
(-1)^(n + 1)/n*x^n
```
Exam the series for convergence
```
(3*n - 1)/(-5)^n
```