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(9*n-7)/2^n
  • How to use it?

  • Sum of series:
  • x^n/n
  • 1/(4n^2-1) 1/(4n^2-1)
  • (1000^n)/n! (1000^n)/n!
  • 2n 2n
  • Identical expressions

  • (nine *n- seven)/ two ^n
  • (9 multiply by n minus 7) divide by 2 to the power of n
  • (nine multiply by n minus seven) divide by two to the power of n
  • (9*n-7)/2n
  • 9*n-7/2n
  • (9n-7)/2^n
  • (9n-7)/2n
  • 9n-7/2n
  • 9n-7/2^n
  • (9*n-7) divide by 2^n
  • Similar expressions

  • (9*n+7)/2^n

Sum of series (9*n-7)/2^n



=

The solution

You have entered [src]
  oo         
____         
\   `        
 \    9*n - 7
  \   -------
  /       n  
 /       2   
/___,        
n = 1        
$$\sum_{n=1}^{\infty} \frac{9 n - 7}{2^{n}}$$
Sum((9*n - 7)/2^n, (n, 1, oo))
The radius of convergence of the power series
Given number:
$$\frac{9 n - 7}{2^{n}}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = 9 n - 7$$
and
$$x_{0} = -2$$
,
$$d = -1$$
,
$$c = 0$$
then
$$\frac{1}{R} = \tilde{\infty} \left(-2 + \lim_{n \to \infty}\left(\frac{\left|{9 n - 7}\right|}{9 n + 2}\right)\right)$$
Let's take the limit
we find
False

$$R = 0$$
The rate of convergence of the power series
The answer [src]
11
$$11$$
11
Numerical answer [src]
11.0000000000000000000000000000
11.0000000000000000000000000000
The graph
Sum of series (9*n-7)/2^n

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