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n^(2*n)/factorial(n)

How to use it?
Sum of series:
6/7
4/(n^2-12n+35)
2*pi*(44+n*0.079)
1/((2*n+1)*(2*n+5))
Limit of the function:
n^(2*n)/factorial(n)
Identical expressions
n^(two *n)/factorial(n)
n to the power of (2 multiply by n) divide by factorial(n)
n to the power of (two multiply by n) divide by factorial(n)
n(2*n)/factorial(n)
n2*n/factorialn
n^(2n)/factorial(n)
n(2n)/factorial(n)
n2n/factorialn
n^2n/factorialn
n^(2*n) divide by factorial(n)

Sum of series/ n^(2*n)/factorial(n)

Sum of series n^(2*n)/factorial(n)

The solution

You have entered [src]

  oo      
____      
\   `     
 \     2*n
  \   n   
  /   ----
 /     n! 
/___,     
n = 1

$$\sum_{n=1}^{\infty} \frac{n^{2 n}}{n!}$$

Sum(n^(2*n)/factorial(n), (n, 1, oo))

The rate of convergence of the power series

The graph

Sum of series n^(2*n)/factorial(n)

Examples of finding the sum of a series

The Sum of the Power Series
```
x^n/n
```
```
(x-1)^n
```
Factorial
```
1/2^(n!)
```
```
n^2/n!
```
```
x^n/n!
```
```
k!/(n!*(n+k)!)
```
Flint Hills Series
```
csc(n)^2/n^3
```
Basel problem
```
1/n^2
```
```
1/n^4
```
```
1/n^6
```
Harmonic series
```
1/n
```
Grandi's series
```
(-1)^n
```
Alternating series
```
(-1)^(n + 1)/n
```
```
(n + 2)*(-1)^(n - 1)
```
```
(3*n - 1)/(-5)^n
```
```
(-1)^(n - 1)*n/(6*n - 5)
```
Newton–Mercator series
```
(-1)^(n + 1)/n*x^n
```
Exam the series for convergence
```
(3*n - 1)/(-5)^n
```