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(n+1)/(n^2*(n+2)^2)
  • How to use it?

  • Sum of series:
  • 1/((2n-1)(2n+3)) 1/((2n-1)(2n+3))
  • (n+1)/(n^2*(n+2)^2) (n+1)/(n^2*(n+2)^2)
  • 1/(nln^2n) 1/(nln^2n)
  • log((n+1)/(n+2)) log((n+1)/(n+2))
  • Identical expressions

  • (n+ one)/(n^ two *(n+ two)^ two)
  • (n plus 1) divide by (n squared multiply by (n plus 2) squared )
  • (n plus one) divide by (n to the power of two multiply by (n plus two) to the power of two)
  • (n+1)/(n2*(n+2)2)
  • n+1/n2*n+22
  • (n+1)/(n²*(n+2)²)
  • (n+1)/(n to the power of 2*(n+2) to the power of 2)
  • (n+1)/(n^2(n+2)^2)
  • (n+1)/(n2(n+2)2)
  • n+1/n2n+22
  • n+1/n^2n+2^2
  • (n+1) divide by (n^2*(n+2)^2)
  • Similar expressions

  • (n-1)/(n^2*(n+2)^2)
  • (n+1)/(n^2*(n-2)^2)

Sum of series (n+1)/(n^2*(n+2)^2)



=

The solution

You have entered [src]
  oo             
____             
\   `            
 \       n + 1   
  \   -----------
  /    2        2
 /    n *(n + 2) 
/___,            
n = 1            
$$\sum_{n=1}^{\infty} \frac{n + 1}{n^{2} \left(n + 2\right)^{2}}$$
Sum((n + 1)/((n^2*(n + 2)^2)), (n, 1, oo))
The radius of convergence of the power series
Given number:
$$\frac{n + 1}{n^{2} \left(n + 2\right)^{2}}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{n + 1}{n^{2} \left(n + 2\right)^{2}}$$
and
$$x_{0} = 0$$
,
$$d = 0$$
,
$$c = 1$$
then
$$1 = \lim_{n \to \infty}\left(\frac{\left(n + 1\right)^{3} \left(n + 3\right)^{2}}{n^{2} \left(n + 2\right)^{3}}\right)$$
Let's take the limit
we find
True

False
The rate of convergence of the power series
The answer [src]
5/16
$$\frac{5}{16}$$
5/16
Numerical answer [src]
0.312500000000000000000000000000
0.312500000000000000000000000000
The graph
Sum of series (n+1)/(n^2*(n+2)^2)

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