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n*3^n+1

Sum of series n*3^n+1



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The solution

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  oo            
 ___            
 \  `           
  \   /   n    \
  /   \n*3  + 1/
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n = 1           
n=1(3nn+1)\sum_{n=1}^{\infty} \left(3^{n} n + 1\right)
Sum(n*3^n + 1, (n, 1, oo))
The radius of convergence of the power series
Given number:
3nn+13^{n} n + 1
It is a series of species
an(cxx0)dna_{n} \left(c x - x_{0}\right)^{d n}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limnanan+1cR^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}
In this case
an=3nn+1a_{n} = 3^{n} n + 1
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=limn(3nn+13n+1(n+1)+1)1 = \lim_{n \to \infty}\left(\frac{3^{n} n + 1}{3^{n + 1} \left(n + 1\right) + 1}\right)
Let's take the limit
we find
False

False

False
The rate of convergence of the power series
1.07.01.52.02.53.03.54.04.55.05.56.06.5025000
The answer [src]
oo
\infty
oo
Numerical answer
The series diverges
The graph
Sum of series n*3^n+1

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