Given number:
$$\frac{87 \frac{\left(\frac{21}{100}\right)^{n} n! \frac{6!}{n! \left(6 - n\right)!} \left(n - 1\right)}{1^{6 - n} 1!}}{500}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{3132 \left(n - 1\right)}{25 \left(6 - n\right)!}$$
and
$$x_{0} = - \frac{21}{100}$$
,
$$d = 1$$
,
$$c = 0$$
then
False
Let's take the limitwe find
False