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factorial(2*n)/(2^n+3)

How to use it?
Sum of series:
(n^3+n+5)/(n+2)
factorial(2*n)/(2^n+3)
sin(π/4)(2n-1)
cos(2n)/(2^n)
Identical expressions
factorial(two *n)/(two ^n+ three)
factorial(2 multiply by n) divide by (2 to the power of n plus 3)
factorial(two multiply by n) divide by (two to the power of n plus three)
factorial(2*n)/(2n+3)
factorial2*n/2n+3
factorial(2n)/(2^n+3)
factorial(2n)/(2n+3)
factorial2n/2n+3
factorial2n/2^n+3
factorial(2*n) divide by (2^n+3)
Similar expressions
factorial(2*n)/(2^n-3)

Sum of series/ factorial(2*n)/(2^n+3)

Sum of series factorial(2*n)/(2^n+3)

The solution

You have entered [src]

  oo        
____        
\   `       
 \    (2*n)!
  \   ------
  /    n    
 /    2  + 3
/___,       
n = 1

$$\sum_{n=1}^{\infty} \frac{\left(2 n\right)!}{2^{n} + 3}$$

Sum(factorial(2*n)/(2^n + 3), (n, 1, oo))

The rate of convergence of the power series

The graph

Sum of series factorial(2*n)/(2^n+3)

Examples of finding the sum of a series

The Sum of the Power Series
```
x^n/n
```
```
(x-1)^n
```
Factorial
```
1/2^(n!)
```
```
n^2/n!
```
```
x^n/n!
```
```
k!/(n!*(n+k)!)
```
Flint Hills Series
```
csc(n)^2/n^3
```
Basel problem
```
1/n^2
```
```
1/n^4
```
```
1/n^6
```
Harmonic series
```
1/n
```
Grandi's series
```
(-1)^n
```
Alternating series
```
(-1)^(n + 1)/n
```
```
(n + 2)*(-1)^(n - 1)
```
```
(3*n - 1)/(-5)^n
```
```
(-1)^(n - 1)*n/(6*n - 5)
```
Newton–Mercator series
```
(-1)^(n + 1)/n*x^n
```
Exam the series for convergence
```
(3*n - 1)/(-5)^n
```