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factorial(n)*3^n/n^n

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  • Sum of series:
  • factorial(n)*3^n/n^n factorial(n)*3^n/n^n
  • ln(1-(1/n^2)) ln(1-(1/n^2))
  • log((-1)^n/3^n)
  • n^n/factorial(n+3) n^n/factorial(n+3)

  • Identical expressions

  • factorial(n)* three ^n/n^n
  • factorial(n) multiply by 3 to the power of n divide by n to the power of n
  • factorial(n) multiply by three to the power of n divide by n to the power of n
  • factorial(n)*3n/nn
  • factorialn*3n/nn
  • factorial(n)3^n/n^n
  • factorial(n)3n/nn
  • factorialn3n/nn
  • factorialn3^n/n^n
  • factorial(n)*3^n divide by n^n
Sum of series/ factorial(n)*3^n/n^n

Sum of series factorial(n)*3^n/n^n


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The solution

You have entered [src] 
  oo       
____       
\   `      
 \        n
  \   n!*3 
   )  -----
  /      n 
 /      n  
/___,      
n = 1
$$\sum_{n=1}^{\infty} \frac{3^{n} n!}{n^{n}}$$ 
Sum((factorial(n)*3^n)/n^n, (n, 1, oo))
The radius of convergence of the power series
Given number:
$$\frac{3^{n} n!}{n^{n}}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = n^{- n} n!$$
and
$$x_{0} = -3$$
,
$$d = 1$$
,
$$c = 0$$
then
$$R = \tilde{\infty} \left(-3 + \lim_{n \to \infty}\left(n^{- n} \left(n + 1\right)^{n + 1} \left|{\frac{n!}{\left(n + 1\right)!}}\right|\right)\right)$$
Let's take the limit
we find
False

False
The rate of convergence of the power series
The answer [src] 
  oo           
 ___           
 \  `          
  \    n  -n   
  /   3 *n  *n!
 /__,          
n = 1
$$\sum_{n=1}^{\infty} 3^{n} n^{- n} n!$$ 
Sum(3^n*n^(-n)*factorial(n), (n, 1, oo))
The graph
Sum of series factorial(n)*3^n/n^n

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