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cos(k)/2^k
  • How to use it?

  • Sum of series:
  • (-1/2)^n (-1/2)^n
  • 1/(3n+1)(3n+4) 1/(3n+1)(3n+4)
  • e^(-n) e^(-n)
  • 1/((5n-4)(5n+1)) 1/((5n-4)(5n+1))
  • Identical expressions

  • cos(k)/ two ^k
  • co sinus of e of (k) divide by 2 to the power of k
  • co sinus of e of (k) divide by two to the power of k
  • cos(k)/2k
  • cosk/2k
  • cosk/2^k
  • cos(k) divide by 2^k

Sum of series cos(k)/2^k



=

The solution

You have entered [src]
  n         
____        
\   `       
 \    cos(k)
  \   ------
  /      k  
 /      2   
/___,       
k = 1       
$$\sum_{k=1}^{n} \frac{\cos{\left(k \right)}}{2^{k}}$$
Sum(cos(k)/2^k, (k, 1, n))
The rate of convergence of the power series
The answer [src]
  n             
 ___            
 \  `           
  \    -k       
  /   2  *cos(k)
 /__,           
k = 1           
$$\sum_{k=1}^{n} 2^{- k} \cos{\left(k \right)}$$
Sum(2^(-k)*cos(k), (k, 1, n))
The graph
Sum of series cos(k)/2^k

    Examples of finding the sum of a series