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arctg(n)/(1+n^2)
  • How to use it?

  • Sum of series:
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  • 3/((n+2)^2-1) 3/((n+2)^2-1)
  • 2/(x^2+2x)
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  • Identical expressions

  • arctg(n)/(one +n^ two)
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  • arctg(n)/(1+n2)
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  • arctg(n)/(1+n²)
  • arctg(n)/(1+n to the power of 2)
  • arctgn/1+n^2
  • arctg(n) divide by (1+n^2)
  • Similar expressions

  • arctg(n)/(1-n^2)

Sum of series arctg(n)/(1+n^2)



=

The solution

You have entered [src]
  oo         
____         
\   `        
 \    atan(n)
  \   -------
  /         2
 /     1 + n 
/___,        
n = 1        
$$\sum_{n=1}^{\infty} \frac{\operatorname{atan}{\left(n \right)}}{n^{2} + 1}$$
Sum(atan(n)/(1 + n^2), (n, 1, oo))
The radius of convergence of the power series
Given number:
$$\frac{\operatorname{atan}{\left(n \right)}}{n^{2} + 1}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{\operatorname{atan}{\left(n \right)}}{n^{2} + 1}$$
and
$$x_{0} = 0$$
,
$$d = 0$$
,
$$c = 1$$
then
$$1 = \lim_{n \to \infty}\left(\frac{\left(\left(n + 1\right)^{2} + 1\right) \operatorname{atan}{\left(n \right)}}{\left(n^{2} + 1\right) \operatorname{atan}{\left(n + 1 \right)}}\right)$$
Let's take the limit
we find
True

False
The rate of convergence of the power series
Numerical answer [src]
1.13558057875099994273174426656
1.13558057875099994273174426656
The graph
Sum of series arctg(n)/(1+n^2)

    Examples of finding the sum of a series