Mister Exam

Sum of series 3i



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The solution

You have entered [src]
  n      
 __      
 \ `     
  )   3*I
 /_,     
n = 1    
n=1n3i\sum_{n=1}^{n} 3 i
Sum(3*i, (n, 1, n))
The answer [src]
3*I*n
3in3 i n
3*i*n

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