General simplification
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$$6 x^{2} - 4 x y - y^{2}$$
The perfect square
Let's highlight the perfect square of the square three-member
$$6 x^{2} + \left(- x 4 y - y^{2}\right)$$
Let us write down the identical expression
$$6 x^{2} + \left(- x 4 y - y^{2}\right) = - \frac{5 y^{2}}{3} + \left(6 x^{2} - 4 x y + \frac{2 y^{2}}{3}\right)$$
or
$$6 x^{2} + \left(- x 4 y - y^{2}\right) = - \frac{5 y^{2}}{3} + \left(\sqrt{6} x - \frac{\sqrt{6} y}{3}\right)^{2}$$
in the view of the product
$$\left(- \sqrt{\frac{5}{3}} y + \left(\sqrt{6} x + - \frac{\sqrt{6}}{3} y\right)\right) \left(\sqrt{\frac{5}{3}} y + \left(\sqrt{6} x + - \frac{\sqrt{6}}{3} y\right)\right)$$
$$\left(- \frac{\sqrt{15}}{3} y + \left(\sqrt{6} x + - \frac{\sqrt{6}}{3} y\right)\right) \left(\frac{\sqrt{15}}{3} y + \left(\sqrt{6} x + - \frac{\sqrt{6}}{3} y\right)\right)$$
$$\left(\sqrt{6} x + y \left(- \frac{\sqrt{15}}{3} - \frac{\sqrt{6}}{3}\right)\right) \left(\sqrt{6} x + y \left(- \frac{\sqrt{6}}{3} + \frac{\sqrt{15}}{3}\right)\right)$$
$$\left(\sqrt{6} x + y \left(- \frac{\sqrt{15}}{3} - \frac{\sqrt{6}}{3}\right)\right) \left(\sqrt{6} x + y \left(- \frac{\sqrt{6}}{3} + \frac{\sqrt{15}}{3}\right)\right)$$
/ / ____\\ / / ____\\
| y*\2 - \/ 10 /| | y*\2 + \/ 10 /|
|x - --------------|*|x - --------------|
\ 6 / \ 6 /
$$\left(x - \frac{y \left(2 - \sqrt{10}\right)}{6}\right) \left(x - \frac{y \left(2 + \sqrt{10}\right)}{6}\right)$$
(x - y*(2 - sqrt(10))/6)*(x - y*(2 + sqrt(10))/6)
$$6 x^{2} - 4 x y - y^{2}$$
$$6 x^{2} - 4 x y - y^{2}$$
$$6 x^{2} - 4 x y - y^{2}$$
Rational denominator
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$$6 x^{2} - 4 x y - y^{2}$$
Combining rational expressions
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$$6 x^{2} + y \left(- 4 x - y\right)$$
$$6 x^{2} - 4 x y - y^{2}$$
Assemble expression
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$$6 x^{2} - 4 x y - y^{2}$$