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How to use it?
Factor polynomial
:
x^2-3*x+2
x1^2+x2^2
x^3+1
-y^8+y^5
Least common denominator
:
((x+1)^2*(8*x-4))^(1/3)*(8*(x+1)^2/3+(2+2*x)*(8*x-4)/3)/((x+1)^2*(8*x-4))
4*((sin(8*x)/2+4*x)/8-sin(4*x)/2+x)
(49*b/a-25*a/b)/(7*a+5*b)
((y-9)/(y-8))*((y^2-64)/(y^2-16*y-64))
Factor squared
:
-y^4+y^2-3
y^4-y^2-5
x^2+x-2
-y^4+8*y^2-8
How do you in partial fractions?
:
(x^2-x-6)/(x+2)
(m^2-1)/(m+1)
(z-3)/(z+3)*(z+(z^2)/(3-z))
(z-2)/(6*z+(z-2)*(z-2))+(6/(z*z*z-8))
Canonical form
:
x1^2+x2^2
Identical expressions
x1^ two +x two ^2
x1 squared plus x2 squared
x1 to the power of two plus x two squared
x12+x22
x1²+x2²
x1 to the power of 2+x2 to the power of 2
Similar expressions
x1^2-x2^2
Expression simplification
/
Factorization polynomials
/
x1^2+x2^2
Factor polynomial x1^2+x2^2
An expression to simplify:
Factor polynomial
The solution
You have entered
[src]
2 2 x1 + x2
$$x_{1}^{2} + x_{2}^{2}$$
x1^2 + x2^2
Factorization
[src]
(x1 + I*x2)*(x1 - I*x2)
$$\left(x_{1} - i x_{2}\right) \left(x_{1} + i x_{2}\right)$$
(x1 + i*x2)*(x1 - i*x2)
Numerical answer
[src]
x1^2 + x2^2
x1^2 + x2^2