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How do you (x^2-x-2)/(x-2) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2        
x  - x - 2
----------
  x - 2   
$$\frac{\left(x^{2} - x\right) - 2}{x - 2}$$
(x^2 - x - 2)/(x - 2)
General simplification [src]
1 + x
$$x + 1$$
1 + x
Fraction decomposition [src]
1 + x
$$x + 1$$
1 + x
Numerical answer [src]
(-2.0 + x^2 - x)/(-2.0 + x)
(-2.0 + x^2 - x)/(-2.0 + x)
Trigonometric part [src]
      2    
-2 + x  - x
-----------
   -2 + x  
$$\frac{x^{2} - x - 2}{x - 2}$$
(-2 + x^2 - x)/(-2 + x)
Common denominator [src]
1 + x
$$x + 1$$
1 + x
Combining rational expressions [src]
-2 + x*(-1 + x)
---------------
     -2 + x    
$$\frac{x \left(x - 1\right) - 2}{x - 2}$$
(-2 + x*(-1 + x))/(-2 + x)
Combinatorics [src]
1 + x
$$x + 1$$
1 + x
Powers [src]
      2    
-2 + x  - x
-----------
   -2 + x  
$$\frac{x^{2} - x - 2}{x - 2}$$
(-2 + x^2 - x)/(-2 + x)
Assemble expression [src]
      2    
-2 + x  - x
-----------
   -2 + x  
$$\frac{x^{2} - x - 2}{x - 2}$$
(-2 + x^2 - x)/(-2 + x)
Rational denominator [src]
      2    
-2 + x  - x
-----------
   -2 + x  
$$\frac{x^{2} - x - 2}{x - 2}$$
(-2 + x^2 - x)/(-2 + x)