How do you (x^2-3*x+4)/(x-3) in partial fractions?

You have entered [src]

 2          
x  - 3*x + 4
------------
   x - 3

$$\frac{\left(x^{2} - 3 x\right) + 4}{x - 3}$$

(x^2 - 3*x + 4)/(x - 3)

General simplification [src]

     2      
4 + x  - 3*x
------------
   -3 + x

$$\frac{x^{2} - 3 x + 4}{x - 3}$$

(4 + x^2 - 3*x)/(-3 + x)

Fraction decomposition [src]

x + 4/(-3 + x)

$$x + \frac{4}{x - 3}$$

      4   
x + ------
    -3 + x

Numerical answer [src]

(4.0 + x^2 - 3.0*x)/(-3.0 + x)

(4.0 + x^2 - 3.0*x)/(-3.0 + x)

Powers [src]

     2      
4 + x  - 3*x
------------
   -3 + x

$$\frac{x^{2} - 3 x + 4}{x - 3}$$

(4 + x^2 - 3*x)/(-3 + x)

Rational denominator [src]

     2      
4 + x  - 3*x
------------
   -3 + x

$$\frac{x^{2} - 3 x + 4}{x - 3}$$

(4 + x^2 - 3*x)/(-3 + x)

Combinatorics [src]

     2      
4 + x  - 3*x
------------
   -3 + x

$$\frac{x^{2} - 3 x + 4}{x - 3}$$

(4 + x^2 - 3*x)/(-3 + x)

Trigonometric part [src]

     2      
4 + x  - 3*x
------------
   -3 + x

$$\frac{x^{2} - 3 x + 4}{x - 3}$$

(4 + x^2 - 3*x)/(-3 + x)

Combining rational expressions [src]

4 + x*(-3 + x)
--------------
    -3 + x

$$\frac{x \left(x - 3\right) + 4}{x - 3}$$

(4 + x*(-3 + x))/(-3 + x)

Assemble expression [src]

     2      
4 + x  - 3*x
------------
   -3 + x

$$\frac{x^{2} - 3 x + 4}{x - 3}$$

(4 + x^2 - 3*x)/(-3 + x)

Common denominator [src]

      4   
x + ------
    -3 + x

$$x + \frac{4}{x - 3}$$

x + 4/(-3 + x)