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How do you (x^2-1)/(x^3+1) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2    
x  - 1
------
 3    
x  + 1
$$\frac{x^{2} - 1}{x^{3} + 1}$$
(x^2 - 1)/(x^3 + 1)
Fraction decomposition [src]
(-1 + x)/(1 + x^2 - x)
$$\frac{x - 1}{x^{2} - x + 1}$$
  -1 + x  
----------
     2    
1 + x  - x
Combinatorics [src]
  -1 + x  
----------
     2    
1 + x  - x
$$\frac{x - 1}{x^{2} - x + 1}$$
(-1 + x)/(1 + x^2 - x)
Common denominator [src]
  -1 + x  
----------
     2    
1 + x  - x
$$\frac{x - 1}{x^{2} - x + 1}$$
(-1 + x)/(1 + x^2 - x)
Numerical answer [src]
(-1.0 + x^2)/(1.0 + x^3)
(-1.0 + x^2)/(1.0 + x^3)