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How to use it?
How do you in partial fractions?
:
(y/(x-y)+x/(x+y))/(1/x^2+1/y^2)-y^4/(x^2-y^2)
-1/(10*tan(-1/2+5*x/2))+tan(-1/2+5*x/2)/10
x^2/(x+4)
(x^2+x-12)/(x-3)
Factor polynomial
:
z^2+4*z+13
x^2+4*x-5
m^2-n^2+m-n
24*x^6-44*x^4*y-18*x^2*y^3+33*y^4
Least common denominator
:
(z/b+b/z)/z^2+b^(2/7)*z^(16*b)
y-b/(a-a*b)-(y-a)/a*b-b
(x-sin(2*x)/2)/2-2*cos(x)+x
z/4*(x-y)-2*z/x-y
Factor squared
:
-y^4+y^2+2
y^4-6*y^2+4
y^4+4*y^2+12
x^4-2*x^2-1
Integral of d{x}
:
x^2/(x+4)
Graphing y =
:
x^2/(x+4)
Identical expressions
x^ two /(x+ four)
x squared divide by (x plus 4)
x to the power of two divide by (x plus four)
x2/(x+4)
x2/x+4
x²/(x+4)
x to the power of 2/(x+4)
x^2/x+4
x^2 divide by (x+4)
Similar expressions
x^2/(x-4)
Expression simplification
/
Fraction Decomposition into the simple
/
x^2/(x+4)
How do you x^2/(x+4) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 x ----- x + 4
$$\frac{x^{2}}{x + 4}$$
x^2/(x + 4)
Fraction decomposition
[src]
-4 + x + 16/(4 + x)
$$x - 4 + \frac{16}{x + 4}$$
16 -4 + x + ----- 4 + x
Numerical answer
[src]
x^2/(4.0 + x)
x^2/(4.0 + x)
Common denominator
[src]
16 -4 + x + ----- 4 + x
$$x - 4 + \frac{16}{x + 4}$$
-4 + x + 16/(4 + x)