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How do you (x^4-x^2)/(x-1) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 4    2
x  - x 
-------
 x - 1 
$$\frac{x^{4} - x^{2}}{x - 1}$$
(x^4 - x^2)/(x - 1)
Fraction decomposition [src]
x^2 + x^3
$$x^{3} + x^{2}$$
 2    3
x  + x 
General simplification [src]
 2        
x *(1 + x)
$$x^{2} \left(x + 1\right)$$
x^2*(1 + x)
Numerical answer [src]
(x^4 - x^2)/(-1.0 + x)
(x^4 - x^2)/(-1.0 + x)
Common denominator [src]
 2    3
x  + x 
$$x^{3} + x^{2}$$
x^2 + x^3
Combining rational expressions [src]
 2 /      2\
x *\-1 + x /
------------
   -1 + x   
$$\frac{x^{2} \left(x^{2} - 1\right)}{x - 1}$$
x^2*(-1 + x^2)/(-1 + x)
Combinatorics [src]
 2        
x *(1 + x)
$$x^{2} \left(x + 1\right)$$
x^2*(1 + x)