Mister Exam

Lang:

How to use it?
How do you in partial fractions?:
(x^4-x^2)/(x-1)
x^2+1/(x^2)
(m-(14*m-49)/m)/(7/m-1)
e^x/(e^x+2)
Factor polynomial:
x-x^3+5*x^2/2
x-x^3/3+x^5/5+3*x^4/4
x-x^3/3+x^4/4
x-x^3+3*x^2
Least common denominator:
((y^2-49)/(y^2-14*y+49))^4/((y+7)/(y-7))^4
x*((x-1)^2/x^2)*(2/x-2*(x-1)/x^2)/(x-1)
(x-sqrt(6)+8)/(4-sqrt(x))*(2+sqrt(x))*(4/(16+x^2)+x*(4+x)^2/(256-x^4))
(x-sin(2*x)/2)/2-2*cos(x)+x
Factor squared:
-y^2+y-7
-y^2+y+9
-y^2-y-8
-y^2+y-5
Least common denominator:
(m-(14*m-49)/m)/(7/m-1)
Identical expressions
(m-(fourteen *m- forty-nine)/m)/(seven /m- one)
(m minus (14 multiply by m minus 49) divide by m) divide by (7 divide by m minus 1)
(m minus (fourteen multiply by m minus forty minus nine) divide by m) divide by (seven divide by m minus one)
(m-(14m-49)/m)/(7/m-1)
m-14m-49/m/7/m-1
(m-(14*m-49) divide by m) divide by (7 divide by m-1)
Similar expressions
(m-(14*m+49)/m)/(7/m-1)
(m-(14*m-49)/m)/(7/m+1)
(m+(14*m-49)/m)/(7/m-1)

How do you (m-(14*m-49)/m)/(7/m-1) in partial fractions?

You have entered [src]

    14*m - 49
m - ---------
        m    
-------------
    7        
    - - 1    
    m

$$\frac{m - \frac{14 m - 49}{m}}{-1 + \frac{7}{m}}$$

(m - (14*m - 49)/m)/(7/m - 1)

Fraction decomposition [src]

7 - m

$$7 - m$$

7 - m

General simplification [src]

7 - m

$$7 - m$$

7 - m

Numerical answer [src]

(m - (-49.0 + 14.0*m)/m)/(-1.0 + 7.0/m)

(m - (-49.0 + 14.0*m)/m)/(-1.0 + 7.0/m)

Powers [src]

    49 - 14*m
m + ---------
        m    
-------------
         7   
    -1 + -   
         m

$$\frac{m + \frac{49 - 14 m}{m}}{-1 + \frac{7}{m}}$$

(m + (49 - 14*m)/m)/(-1 + 7/m)

Common denominator [src]

7 - m

$$7 - m$$

7 - m

Rational denominator [src]

      2       
49 + m  - 14*m
--------------
    7 - m

$$\frac{m^{2} - 14 m + 49}{7 - m}$$

(49 + m^2 - 14*m)/(7 - m)

Combining rational expressions [src]

      2       
49 + m  - 14*m
--------------
    7 - m

$$\frac{m^{2} - 14 m + 49}{7 - m}$$

(49 + m^2 - 14*m)/(7 - m)

Combinatorics [src]

7 - m

$$7 - m$$

7 - m