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How do you (4x-1)/(x^2-4x+8) in partial fractions?

You have entered [src]

  4*x - 1   
------------
 2          
x  - 4*x + 8

$$\frac{4 x - 1}{\left(x^{2} - 4 x\right) + 8}$$

(4*x - 1)/(x^2 - 4*x + 8)

General simplification [src]

  -1 + 4*x  
------------
     2      
8 + x  - 4*x

$$\frac{4 x - 1}{x^{2} - 4 x + 8}$$

(-1 + 4*x)/(8 + x^2 - 4*x)

Fraction decomposition [src]

(-1 + 4*x)/(8 + x^2 - 4*x)

$$\frac{4 x - 1}{x^{2} - 4 x + 8}$$

  -1 + 4*x  
------------
     2      
8 + x  - 4*x

Numerical answer [src]

(-1.0 + 4.0*x)/(8.0 + x^2 - 4.0*x)

(-1.0 + 4.0*x)/(8.0 + x^2 - 4.0*x)

Trigonometric part [src]

  -1 + 4*x  
------------
     2      
8 + x  - 4*x

$$\frac{4 x - 1}{x^{2} - 4 x + 8}$$

(-1 + 4*x)/(8 + x^2 - 4*x)

Assemble expression [src]

  -1 + 4*x  
------------
     2      
8 + x  - 4*x

$$\frac{4 x - 1}{x^{2} - 4 x + 8}$$

(-1 + 4*x)/(8 + x^2 - 4*x)

Powers [src]

  -1 + 4*x  
------------
     2      
8 + x  - 4*x

$$\frac{4 x - 1}{x^{2} - 4 x + 8}$$

(-1 + 4*x)/(8 + x^2 - 4*x)

Combining rational expressions [src]

   -1 + 4*x   
--------------
8 + x*(-4 + x)

$$\frac{4 x - 1}{x \left(x - 4\right) + 8}$$

(-1 + 4*x)/(8 + x*(-4 + x))

Common denominator [src]

  -1 + 4*x  
------------
     2      
8 + x  - 4*x

$$\frac{4 x - 1}{x^{2} - 4 x + 8}$$

(-1 + 4*x)/(8 + x^2 - 4*x)

Rational denominator [src]

  -1 + 4*x  
------------
     2      
8 + x  - 4*x

$$\frac{4 x - 1}{x^{2} - 4 x + 8}$$

(-1 + 4*x)/(8 + x^2 - 4*x)

Combinatorics [src]

  -1 + 4*x  
------------
     2      
8 + x  - 4*x

$$\frac{4 x - 1}{x^{2} - 4 x + 8}$$

(-1 + 4*x)/(8 + x^2 - 4*x)