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How do you 2x/(x^2+1)^2 in partial fractions?

An expression to simplify:

The solution

You have entered [src]
   2*x   
---------
        2
/ 2    \ 
\x  + 1/ 
$$\frac{2 x}{\left(x^{2} + 1\right)^{2}}$$
(2*x)/(x^2 + 1)^2
Fraction decomposition [src]
2*x/(1 + x^2)^2
$$\frac{2 x}{\left(x^{2} + 1\right)^{2}}$$
   2*x   
---------
        2
/     2\ 
\1 + x / 
Numerical answer [src]
2.0*x/(1.0 + x^2)^2
2.0*x/(1.0 + x^2)^2
Common denominator [src]
     2*x     
-------------
     4      2
1 + x  + 2*x 
$$\frac{2 x}{x^{4} + 2 x^{2} + 1}$$
2*x/(1 + x^4 + 2*x^2)