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How do you (2*x^5-10*x^4+20*x^3-32*x^2+16*x)/(x^2-2*x)^4 in partial fractions?

An expression to simplify:

The solution

You have entered [src]
   5       4       3       2       
2*x  - 10*x  + 20*x  - 32*x  + 16*x
-----------------------------------
                      4            
            / 2      \             
            \x  - 2*x/             
$$\frac{16 x + \left(- 32 x^{2} + \left(20 x^{3} + \left(2 x^{5} - 10 x^{4}\right)\right)\right)}{\left(x^{2} - 2 x\right)^{4}}$$
(2*x^5 - 10*x^4 + 20*x^3 - 32*x^2 + 16*x)/(x^2 - 2*x)^4
Fraction decomposition [src]
x^(-3) - 2/(-2 + x)^4 + 2/(-2 + x)^3 - 1/(2*(-2 + x)^2) - 1/(4*x) + 1/(4*(-2 + x))
$$\frac{1}{4 \left(x - 2\right)} - \frac{1}{2 \left(x - 2\right)^{2}} + \frac{2}{\left(x - 2\right)^{3}} - \frac{2}{\left(x - 2\right)^{4}} - \frac{1}{4 x} + \frac{1}{x^{3}}$$
1        2           2            1         1        1     
-- - --------- + --------- - ----------- - --- + ----------
 3           4           3             2   4*x   4*(-2 + x)
x    (-2 + x)    (-2 + x)    2*(-2 + x)                    
General simplification [src]
  /     4             3       2\
2*\8 + x  - 16*x - 5*x  + 10*x /
--------------------------------
           3         4          
          x *(-2 + x)           
$$\frac{2 \left(x^{4} - 5 x^{3} + 10 x^{2} - 16 x + 8\right)}{x^{3} \left(x - 2\right)^{4}}$$
2*(8 + x^4 - 16*x - 5*x^3 + 10*x^2)/(x^3*(-2 + x)^4)
Numerical answer [src]
0.0625*(2.0*x^5 + 16.0*x + 20.0*x^3 - 32.0*x^2 - 10.0*x^4)/(-x + 0.5*x^2)^4
0.0625*(2.0*x^5 + 16.0*x + 20.0*x^3 - 32.0*x^2 - 10.0*x^4)/(-x + 0.5*x^2)^4
Common denominator [src]
                 3      4       2
 16 - 32*x - 10*x  + 2*x  + 20*x 
---------------------------------
 7       4      6       3       5
x  - 32*x  - 8*x  + 16*x  + 24*x 
$$\frac{2 x^{4} - 10 x^{3} + 20 x^{2} - 32 x + 16}{x^{7} - 8 x^{6} + 24 x^{5} - 32 x^{4} + 16 x^{3}}$$
(16 - 32*x - 10*x^3 + 2*x^4 + 20*x^2)/(x^7 - 32*x^4 - 8*x^6 + 16*x^3 + 24*x^5)
Assemble expression [src]
      2       4      5              3
- 32*x  - 10*x  + 2*x  + 16*x + 20*x 
-------------------------------------
                       4             
             / 2      \              
             \x  - 2*x/              
$$\frac{2 x^{5} - 10 x^{4} + 20 x^{3} - 32 x^{2} + 16 x}{\left(x^{2} - 2 x\right)^{4}}$$
(-32*x^2 - 10*x^4 + 2*x^5 + 16*x + 20*x^3)/(x^2 - 2*x)^4
Rational denominator [src]
      2       4      5              3
- 32*x  - 10*x  + 2*x  + 16*x + 20*x 
-------------------------------------
                       4             
             / 2      \              
             \x  - 2*x/              
$$\frac{2 x^{5} - 10 x^{4} + 20 x^{3} - 32 x^{2} + 16 x}{\left(x^{2} - 2 x\right)^{4}}$$
(-32*x^2 - 10*x^4 + 2*x^5 + 16*x + 20*x^3)/(x^2 - 2*x)^4
Combining rational expressions [src]
2*(8 + x*(-16 + x*(10 + x*(-5 + x))))
-------------------------------------
              3         4            
             x *(-2 + x)             
$$\frac{2 \left(x \left(x \left(x \left(x - 5\right) + 10\right) - 16\right) + 8\right)}{x^{3} \left(x - 2\right)^{4}}$$
2*(8 + x*(-16 + x*(10 + x*(-5 + x))))/(x^3*(-2 + x)^4)
Trigonometric part [src]
      2       4      5              3
- 32*x  - 10*x  + 2*x  + 16*x + 20*x 
-------------------------------------
                       4             
             / 2      \              
             \x  - 2*x/              
$$\frac{2 x^{5} - 10 x^{4} + 20 x^{3} - 32 x^{2} + 16 x}{\left(x^{2} - 2 x\right)^{4}}$$
(-32*x^2 - 10*x^4 + 2*x^5 + 16*x + 20*x^3)/(x^2 - 2*x)^4
Powers [src]
      2       4      5              3
- 32*x  - 10*x  + 2*x  + 16*x + 20*x 
-------------------------------------
                       4             
             / 2      \              
             \x  - 2*x/              
$$\frac{2 x^{5} - 10 x^{4} + 20 x^{3} - 32 x^{2} + 16 x}{\left(x^{2} - 2 x\right)^{4}}$$
(-32*x^2 - 10*x^4 + 2*x^5 + 16*x + 20*x^3)/(x^2 - 2*x)^4
Combinatorics [src]
  /     4             3       2\
2*\8 + x  - 16*x - 5*x  + 10*x /
--------------------------------
           3         4          
          x *(-2 + x)           
$$\frac{2 \left(x^{4} - 5 x^{3} + 10 x^{2} - 16 x + 8\right)}{x^{3} \left(x - 2\right)^{4}}$$
2*(8 + x^4 - 16*x - 5*x^3 + 10*x^2)/(x^3*(-2 + x)^4)