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Expression simplification/ Fraction Decomposition into the simple/ (t^3+1)/(t^2-t+t)

How do you (t^3+1)/(t^2-t+t) in partial fractions?

An expression to simplify:

The solution

You have entered [src] 
   3      
  t  + 1  
----------
 2        
t  - t + t
$$\frac{t^{3} + 1}{t + \left(t^{2} - t\right)}$$ 
(t^3 + 1)/(t^2 - t + t)
Fraction decomposition [src] 
t + t^(-2)
$$t + \frac{1}{t^{2}}$$ 
    1 
t + --
     2
    t
General simplification [src] 
    1 
t + --
     2
    t
$$t + \frac{1}{t^{2}}$$ 
t + t^(-2)
Numerical answer [src] 
(1.0 + t^3)/t^2
(1.0 + t^3)/t^2
Common denominator [src] 
    1 
t + --
     2
    t
$$t + \frac{1}{t^{2}}$$ 
t + t^(-2)
Combinatorics [src] 
        /     2    \
(1 + t)*\1 + t  - t/
--------------------
          2         
         t
$$\frac{\left(t + 1\right) \left(t^{2} - t + 1\right)}{t^{2}}$$ 
(1 + t)*(1 + t^2 - t)/t^2
Trigonometric part [src] 
     3
1 + t 
------
   2  
  t
$$\frac{t^{3} + 1}{t^{2}}$$ 
(1 + t^3)/t^2
Assemble expression [src] 
     3
1 + t 
------
   2  
  t
$$\frac{t^{3} + 1}{t^{2}}$$ 
(1 + t^3)/t^2
Combining rational expressions [src] 
     3
1 + t 
------
   2  
  t
$$\frac{t^{3} + 1}{t^{2}}$$ 
(1 + t^3)/t^2
Powers [src] 
     3
1 + t 
------
   2  
  t
$$\frac{t^{3} + 1}{t^{2}}$$ 
(1 + t^3)/t^2
Rational denominator [src] 
     3
1 + t 
------
   2  
  t
$$\frac{t^{3} + 1}{t^{2}}$$ 
(1 + t^3)/t^2
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