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How do you -1/(x+1)^2 in partial fractions?

An expression to simplify:

The solution

You have entered [src]
  -1    
--------
       2
(x + 1) 
$$- \frac{1}{\left(x + 1\right)^{2}}$$
-1/(x + 1)^2
Fraction decomposition [src]
-1/(1 + x)^2
$$- \frac{1}{\left(x + 1\right)^{2}}$$
  -1    
--------
       2
(1 + x) 
Numerical answer [src]
-1/(1.0 + x)^2
-1/(1.0 + x)^2
Common denominator [src]
    -1      
------------
     2      
1 + x  + 2*x
$$- \frac{1}{x^{2} + 2 x + 1}$$
-1/(1 + x^2 + 2*x)