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How do you -1/(x-1)^2 in partial fractions?

An expression to simplify:

The solution

You have entered [src]
  -1    
--------
       2
(x - 1) 
$$- \frac{1}{\left(x - 1\right)^{2}}$$
-1/(x - 1)^2
Fraction decomposition [src]
-1/(-1 + x)^2
$$- \frac{1}{\left(x - 1\right)^{2}}$$
   -1    
---------
        2
(-1 + x) 
Numerical answer [src]
-1/(-1.0 + x)^2
-1/(-1.0 + x)^2
Common denominator [src]
    -1      
------------
     2      
1 + x  - 2*x
$$- \frac{1}{x^{2} - 2 x + 1}$$
-1/(1 + x^2 - 2*x)