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How to use it?
How do you in partial fractions?
:
(x^2-12)/(x-3)-x/(3-x)
(a-b)^2/(b-a)^2
-1/(5*x^5)
(x^2-6*x+8)/(x-4)
Factor polynomial
:
c^5+1
x^2-4*x-5
x^2-x^3
x^2-x-1
Least common denominator
:
(z-6*z/z+3)/z-3/z+3
z-6*z/z+1/z-5/z+1
(z-3)/(z+3)*(z+(z^2)/(3-z))
(((z^2)+(6*z+4))/((z^3)+8))/(1/-1)
Factor squared
:
-y^4+9*y^2+5
y^4-y^2-1
y^4-9*y^2+4
y^4+9*y^2+5
Identical expressions
- one /(five *x^ five)
minus 1 divide by (5 multiply by x to the power of 5)
minus one divide by (five multiply by x to the power of five)
-1/(5*x5)
-1/5*x5
-1/(5*x⁵)
-1/(5x^5)
-1/(5x5)
-1/5x5
-1/5x^5
-1 divide by (5*x^5)
Similar expressions
1/(5*x^5)
Expression simplification
/
Fraction Decomposition into the simple
/
-1/(5*x^5)
How do you -1/(5*x^5) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
-1 ---- 5 5*x
$$- \frac{1}{5 x^{5}}$$
-1/(5*x^5)
Fraction decomposition
[src]
-1/(5*x^5)
$$- \frac{1}{5 x^{5}}$$
-1 ---- 5 5*x
Numerical answer
[src]
-0.2/x^5
-0.2/x^5