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x^2-x^4
Limit of the function/ x^2-x^4

Limit of the function x^2-x^4

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You have entered [src] 
     / 2    4\
 lim \x  - x /
x->1+
lim⁡x→1+(−x4+x2)\lim_{x \to 1^+}\left(- x^{4} + x^{2}\right) 
Limit(x^2 - x^4, x, 1)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
-2.0-1.5-1.0-0.52.00.00.51.01.5-2010
Plot the graph
One‐sided limits [src] 
     / 2    4\
 lim \x  - x /
x->1+
lim⁡x→1+(−x4+x2)\lim_{x \to 1^+}\left(- x^{4} + x^{2}\right) 
0
00 
= 1.63602817918362e-31
     / 2    4\
 lim \x  - x /
x->1-
lim⁡x→1−(−x4+x2)\lim_{x \to 1^-}\left(- x^{4} + x^{2}\right) 
0
00 
= 4.37637022617069e-30
= 4.37637022617069e-30
Other limits x→0, -oo, +oo, 1
lim⁡x→1−(−x4+x2)=0\lim_{x \to 1^-}\left(- x^{4} + x^{2}\right) = 0
More at x→1 from the left
lim⁡x→1+(−x4+x2)=0\lim_{x \to 1^+}\left(- x^{4} + x^{2}\right) = 0
lim⁡x→∞(−x4+x2)=−∞\lim_{x \to \infty}\left(- x^{4} + x^{2}\right) = -\infty
More at x→oo
lim⁡x→0−(−x4+x2)=0\lim_{x \to 0^-}\left(- x^{4} + x^{2}\right) = 0
More at x→0 from the left
lim⁡x→0+(−x4+x2)=0\lim_{x \to 0^+}\left(- x^{4} + x^{2}\right) = 0
More at x→0 from the right
lim⁡x→−∞(−x4+x2)=−∞\lim_{x \to -\infty}\left(- x^{4} + x^{2}\right) = -\infty
More at x→-oo
Rapid solution [src] 
0
00
Expand and simplify
Numerical answer [src] 
1.63602817918362e-31
1.63602817918362e-31
The graph
Limit of the function x^2-x^4
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