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Limit of the function x^2/y^2

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     / 2\
     |x |
 lim |--|
x->oo| 2|
     \y /
limx(x2y2)\lim_{x \to \infty}\left(\frac{x^{2}}{y^{2}}\right)
Limit(x^2/y^2, x, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
Rapid solution [src]
       /1 \
oo*sign|--|
       | 2|
       \y /
sign(1y2)\infty \operatorname{sign}{\left(\frac{1}{y^{2}} \right)}
Other limits x→0, -oo, +oo, 1
limx(x2y2)=sign(1y2)\lim_{x \to \infty}\left(\frac{x^{2}}{y^{2}}\right) = \infty \operatorname{sign}{\left(\frac{1}{y^{2}} \right)}
limx0(x2y2)=0\lim_{x \to 0^-}\left(\frac{x^{2}}{y^{2}}\right) = 0
More at x→0 from the left
limx0+(x2y2)=0\lim_{x \to 0^+}\left(\frac{x^{2}}{y^{2}}\right) = 0
More at x→0 from the right
limx1(x2y2)=1y2\lim_{x \to 1^-}\left(\frac{x^{2}}{y^{2}}\right) = \frac{1}{y^{2}}
More at x→1 from the left
limx1+(x2y2)=1y2\lim_{x \to 1^+}\left(\frac{x^{2}}{y^{2}}\right) = \frac{1}{y^{2}}
More at x→1 from the right
limx(x2y2)=sign(1y2)\lim_{x \to -\infty}\left(\frac{x^{2}}{y^{2}}\right) = \infty \operatorname{sign}{\left(\frac{1}{y^{2}} \right)}
More at x→-oo