We have indeterminateness of type
oo/oo,
i.e. limit for the numerator is
x→∞lim(x−atan(x))=∞and limit for the denominator is
x→∞limx2=∞Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
x→∞lim(x2x−atan(x))=
x→∞lim(dxdx2dxd(x−atan(x)))=
x→∞lim(2x1−x2+11)=
x→∞lim(dxd2xdxd(1−x2+11))=
x→∞lim((x2+1)2x)=
x→∞lim((x2+1)2x)=
0It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 2 time(s)